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(2004•青岛)用换元法解方程x2+x+1=时,若设x2+x=y,则原方程可化为A.y2...
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(2004•青岛)用换元法解方程x
2+x+1=
![](data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAB4AAAAqCAYAAACk2+sZAAAAAXNSR0IArs4c6QAAAARnQU1BAACx
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6ubRTMTpKBcBa2o5eucLfCeb01hZK1eC+dv/DAZiJ+YrLjuHzAgTqqkRNJHp3Gm2hiFwiqE3gmKV
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VD+5/3nAP/y6fJpys2TsAAAAAElFTkSuQmCC
)
时,若设x
2+x=y,则原方程可化为( )
A.y
2+y+2=0
B.y
2-y-2=0
C.y
2-y+2=0
D.y
2+y-2=0
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