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已知[(x2+y2)-(x-y)2+2y(x-y)]÷4y=1,求-的值.
试题详情
已知[(x
2+y
2)-(x-y)
2+2y(x-y)]÷4y=1,求
![](data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAACgAAAAqCAYAAADBNhlmAAAAAXNSR0IArs4c6QAAAARnQU1BAACx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)
-
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jwv8YQUAAAAJcEhZcwAADsMAAA7DAcdvqGQAAAFhSURBVFhH7ZdRroQgDEW7MvbUlcw/m+lSWEpf
q4CgxQnoRPKiiZmPUTm9vVwAeIILJmDgfwARPDtw7MM1PceVIGQAkPtJiKV4YnwhXiWqifB6Isnx
tBJLUGlOrDfSeGCNh9X4mIc3X4gkyRxKJGM99atqzKHEjSYf/tRESuQNigSP83xxo9StCLAmX447
jWEB6Y0/KaL3lZIUAlFVefCuX42rEAfttDWprNSm3KKo1L5lBgRhXFfKZ/V7RrsPxtSXa2kDe6eb
WQVA2VWuVx6kWMS2rInPGbtx8kfP1RCVPzaNlhYVAJZ6tif2Sz2xN84HBYRWvFVaDaRwZ7Om6Ym1
fQkwiArWip8hCNvnBxIlTg85TQgtLEJIIdg4JS0QKnclZ/HR9F/2ijXgFwgnCuCJkmAbDPkT3e0S
fZopnYGwfr/R5tjzn8e2NRv2xr4fIpu48MOXIL8fYuCgfD9E9/LF/AeVabnOBLKnGwAAAABJRU5E
rkJggg==
)
的值.
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填空:
(1)已知(x2+y2+1)(x2+y2-3)=5,则x2+y2的值等于________.
(2)已知实数x、y满足x2-2x+4y=5,则x+2y的最大值为________.
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-
下列是因式分解,且正确的( )
A.(x+2y)2=x2+4xy+4y2
B.(x-y)2+4xy=(x+y)2
C.(2x+y)2-(x+2y)2=(3x+3y)(x-y)
D.-x2+2xy-y2=(x-y)2
-
已知0≤x≤1.
(1)若x-2y=6,则y的最小值是 ________;
(2)若x2+y2=3,xy=1,则x-y=________.
-
计算(-x2y)2的结果是( )
A.-x4y
B.x2y2
C.x4y2
D.2x4y2