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(1)计算:+(-1)2009+(π-2);(2)已知x2-5x=3,求(x-1)(2x-...
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(1)计算:
+(-1)
2009+(π-2);
(2)已知x
2-5x=3,求(x-1)(2x-1)-(x+1)
2+1的值.
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