↑ 收起筛选 ↑
试题详情

下面均是正丁烷与氧气反应的热化学方程式(25℃,101 kPa):

①C4H10(g)+O2(g)=4CO2(g)+5H2O(l)   ΔH=-2878 kJ/mol

②C4H10(g)+O2(g)=4CO2(g)+5H2O(g)   ΔH=-2658 kJ/mol

③C4H10(g)+O2(g)=4CO(g)+5H2O(l)    ΔH=-1746 kJ/mol

④C4H10(g)+O2(g)=4CO(g)+5H2O(g)    ΔH=-1526 kJ/mol

由此判断,正丁烷的燃烧热是

A.-2878 kJ/mol     B.-2658 kJ/mol

C.-1746 kJ/mol     D.-1526 kJ/mol

高二化学选择题中等难度题

少年,再来一题如何?
试题答案
试题解析
相关试题