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下面均是正丁烷与氧气反应的热化学方程式(25℃,101 kPa):

①C4H10(g)+O2(g)===4CO2(g)+5H2O(l)           ΔH=-2878 kJ/mol

②C4H10(g)+O2(g)===4CO2(g)+5H2O(g)   ΔH=-2658 kJ/mol

③C4H10(g)+O2(g)===4CO(g)+5H2O(l)             ΔH=-1746 kJ/mol

④C4H10(g)+O2(g)===4CO(g)+5H2O(g)            ΔH=-1526 kJ/mol

由此判断,正丁烷的燃烧热是:

A.-2878 kJ/mol                     B.-2658 kJ/mol

C.-1746 kJ/mol                         D.-1526 kJ/mol

高一化学选择题简单题

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