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设数列{an}的前n项和为Sn=2n2,{bn}为等比数列,且a1=b1,b2(a2-a1...
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设数列{a
n}的前n项和为S
n=2n
2,{b
n}为等比数列,且a
1=b
1,b
2(a
2-a
1)=b
1.
(Ⅰ)求数列{a
n}和{b
n}的通项公式;
(Ⅱ)设c
n=
![](data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAABEAAAAxCAYAAAA8wULMAAAAAXNSR0IArs4c6QAAAARnQU1BAACx
jwv8YQUAAAAgY0hSTQAAeiYAAICEAAD6AAAAgOgAAHUwAADqYAAAOpgAABdwnLpRPAAAAUJJREFU
SEvtVtuRwyAMVFpWO3RCHVRBEzo9IMbmHCR7Jh+e8JPczLFIuyttXsQH7h4BuXvgLoB28liQQgmA
lULKJRNCouLs1TipcokvV/2DMjJY8kIosXZpvFMSEBqi6wCVdHhVQHtVLgwCeXWsomYkwMz1+c8O
RAGY3EgrZjZpR1Wxy1JZFOgbjm3eUY7G73u+PldSK1VuF3Nhxdh86qfZhMt21DMMoLaZ7GAVLUCk
BWQLmOBHO/SmPoOML5+0sqxk93K3wj8zteTE49ungfS5ufq5VMdD6nNBhriI7MVG2mY2mY3gbp0G
UPZrdLdOICVxTOS+b/3pN0jcOGkTerY3znxjnBw2lrQWSFHbbNrKW5ULCcgQlEZVLqik4bWpYjs1
kOV9UbefEpqCMVV8i9o5xo7I4Ap/CbjR+UtAp7Xmf/sDHHXis+rUVWcAAAAASUVORK5CYII=
)
,求数列{c
n}的前n项和T
n.
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