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设数列设数列{an}的前n项和为Sn,且Sn2-2Sn-ansn+1=0,n=1,2,3…...
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设数列设数列{a
n}的前n项和为S
n,且S
n2-2S
n-a
ns
n+1=0,n=1,2,3…
(1)求a
1,a
2;
(2)求证:数列{
}是等差数列,并求S
n的表达式.
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设数列设数列{an}的前n项和为Sn,且Sn2-2Sn-ansn+1=0,n=1,2,3…
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